This section contains carefully selected MCQs and Previous Year Questions with explanations to help students understand concepts and prepare effectively for examinations, interviews, and competitive tests.
Q: 1Which is the largest unit of storage among the following?
Option A
Memory storage refers to devices or media used to store data and programs in a computer.
Storage units are used to measure the amount of data in a computer, starting from the smallest unit, a bit, to larger units like Byte, Kilobyte (KB), Megabyte (MB), Gigabyte (GB), and Terabyte (TB).
| Storage Unit | Abbreviation | Equivalent |
|---|---|---|
| Bit | b | Smallest unit of data either 0 or 1 |
| Byte | B | 8 Bits |
| Kilobyte | KB | 1024 Bytes |
| Megabyte | MB | 1024 KB |
| Gigabyte | GB | 1024 MB |
| Terabyte | TB | 1024 GB |
| Petabyte | PB | 1024 TB |
| Exabyte | EB | 1024 PB |
| Zettabyte | ZB | 1024 EB |
| Yottabyte | YB | 1024 ZB |
Q: 2Octal representation of decimal 16 is
Option A
To convert a decimal number to octal, we repeatedly divide the number by 8 and record the remainders.
Q: 3Which of the following statement is/are correct?
I. (1071)10 = (2057)8
II. (1AF)16 = (413)10
Option A
We need to check both statements by converting the given numbers into decimal form.
Statement I: (1071)₁₀ = (2057)₈
Convert (2057)₈ into decimal:
(2057)₈ = 2*8³ + 0*8² + 5*8¹ + 7*8⁰
= 2*512 + 0*64 + 5*8 + 7*1
= 1024+0+40+7
= 1071
Therefore, (2057)₈ = (1071)₁₀. Hence, Statement I is TRUE.
Statement II: (1AF)₁₆ = (413)₁₀
In hexadecimal, A = 10 and F = 15.
(1AF)₁₆ = 1*16² + 10*16¹ + 15*16⁰
= 1*256 + 10*16 + 15*1
= 256+160+15
= 431
Therefore, (1AF)₁₆ = (431)₁₀, not (413)₁₀. Hence, Statement II is FALSE.
Q: 4What is the 2’s complement of the binary number 01010101?
Option A
Q: 5Which of the following units of memory of computer is wrongly paired?
Option B
Storage units are used to measure the amount of data in a computer, starting from the smallest unit, a bit, to larger units like byte, kilobyte (KB), megabyte (MB), gigabyte (GB), and terabyte (TB).
| Storage Unit | Abbreviation | Equivalent |
|---|---|---|
| Bit | b | Smallest unit of data either 0 or 1 |
| Byte | B | 8 Bits |
| Kilobyte | KB | 1024 Bytes |
| Megabyte | MB | 1024 KB |
| Gigabyte | GB | 1024 MB |
| Terabyte | TB | 1024 GB |
| Petabyte | PB | 1024 TB |
| Exabyte | EB | 1024 PB |
| Zettabyte | ZB | 1024 EB |
| Yottabyte | YB | 1024 ZB |
Q: 6The BCD equivalent for decimal 15 is?
Option B
BCD (Binary Coded Decimal) is a coding system where each decimal digit is represented separately by its 4-bit binary equivalent.
BCD does not convert the entire number into pure binary. Instead, it converts each digit individually.
| DECIMAL DIGIT | 4-BIT BCD |
|---|---|
| 1 | 0001 |
| 5 | 0101 |
Q: 7What does CSA stand for?
Option B
CSA stands for Computer Speed Addition. It refers to techniques used in computer arithmetic to perform addition faster, often by reducing the time required to handle carries during binary addition.
By designing circuits that can process sums and carries efficiently, computers can speed up arithmetic operations, which is critical in processors and digital systems.
Q: 8Write the binary code for EXAM in ASCII-7. (decimal code of A is 65)
Option B
In ASCII-7, each character is represented by exactly 7 bits. The decimal ASCII code of uppercase A is given as 65. Since uppercase letters have consecutive ASCII codes, we can calculate the codes of the other letters from their positions relative to A.
| Character | ASCII Decimal Code | 7-bit Binary Code |
|---|---|---|
| E | 69 | 1000101 |
| X | 88 | 1011000 |
| A | 65 | 1000001 |
| M | 77 | 1001101 |
Now combine the 7-bit codes in the same order as the word EXAM: 1000101101100010000011001101.
Q: 9If x and y are two decimal numbers such as (0.11101)2 = (0.90xy5)10, what are the values of x and y?
Option B
Convert the binary number to decimal.
(0.11101)2
=1*2-1+1*2-2+1*2-3+0*2-4+1*2-5
=0.5+0.25+0.125+0+0.03125
=0.90625
The decimal form is written as (0.90xy5)10.
Comparing with 0.90625, we get, 0.90xy5 = 0.90625
So the digits must be:
Q: 10Repeated division method by 2 is used to convert _________ to _________.
Option A
The repeated division method by 2 is used to convert a decimal (base 10) number into a binary (base 2) number.
Steps:
1. Divide the decimal number by 2.
2. Record the remainder.
3. Use the quotient for the next division by 2.
4. Repeat until the quotient becomes 0.
5. The binary number is formed by reading the remainders from bottom to top.
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