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Q: 1 Find output of the following program?
void main()
{
int a,b;
for(a=1,b=1;a<5,b<10;b++)
cout<<a;
}

Expression syntax error occurred
Prints values from 1 to 9
Prints 1 nine time
Loop made infinite

Show Answer

[ Option C ]

Here, the important point is the comma operator used in the for-loop condition.
for(a=1,b=1; a<5,b<10; b++)
cout << a;
In a for loop, the condition part can use the comma operator (,). When the comma operator is used, all expressions are evaluated, but the result of the last expression decides the loop condition.

The a<5 is evaluated but its result is ignored.
The b<10 is the last expression, so it controls the loop.
The a is initialized to 1 and is never changed inside the loop.
The b starts from 1 and is incremented each iteration.
The loop runs as long as b<10, i.e., for b=1 to 9.
Each time, cout<<a; prints the value of a, which is always 1.

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