ELEVATE SKILLS!
Output of the linked list node access in the following code:
struct node
{
int data;
struct node* next;
};
int main()
{
struct node n1 = {10,NULL};
struct node n2 = {20,NULL};
n1.next = &n2;
printf(“%d”, n1.data+n1.next->data);
}
10
20
NULL
30
[ Option D ]
In this program, n1 is initialized with data 10 and n2 with data 20. Then n1.next is set to point to n2. In the printf statement, n1.data gives 10 and n1.next->data accesses the data of n2, which is 20. Their sum is 30, so the output is 30.
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